integral of (cos(x)+1/8 x)

Lösung

\int (cos (x) + \frac{1}{8} x) d x

sin (x) + \frac{x ^{2}}{16} + C

Schritte zur Lösung

\int cos (x) + \frac{1}{8} x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x + \int \frac{1}{8} x d x

\int cos (x) d x = sin (x)

\int \frac{1}{8} x d x = \frac{x ^{2}}{16}

= sin (x) + \frac{x ^{2}}{16}

Füge eine Konstante zur Lösung hinzu

= sin (x) + \frac{x ^{2}}{16} + C

x \to 3 - lim (e^{\frac{2}{3 - x}})

(2 y - x^{3}) d x = x d y

\int_{5}^{10} e^{x} d x

\int \frac{1}{3 cos ( x ) - 4 sin ( x )} d x

x \to - 8 - lim (\frac{x + 3}{x + 8})