What is the derivative of f(x)=sqrt(x)+x^{2/3}-3x ?

The derivative of f(x)=sqrt(x)+x^{2/3}-3x is 1/(2x^{1/2)}+2/(3x^{1/3)}-3

What is the first derivative of f(x)=sqrt(x)+x^{2/3}-3x ?

The first derivative of f(x)=sqrt(x)+x^{2/3}-3x is 1/(2x^{1/2)}+2/(3x^{1/3)}-3

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derivative of

f (x) = x + x^{\frac{2}{3}} - 3 x

\frac{1}{2 x ^{\frac{1}{2}}} + \frac{2}{3 x ^{\frac{1}{3}}} - 3

Solution steps

\frac{d}{d x} (x + x^{\frac{2}{3}} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (x^{\frac{2}{3}}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x) = \frac{1}{2 x ^{\frac{1}{2}}}

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} (3 x) = 3

= \frac{1}{2 x ^{\frac{1}{2}}} + \frac{2}{3 x ^{\frac{1}{3}}} - 3

x \to 0 lim (2 sin (x) ln (x))

2 e^{x} - e^{x + 1} + e^{\frac{2}{3}} - 5 π^{2}

x \to 0 + lim (sin^{2} (x))

n = 0 \sum \infty (\frac{3}{2})^{n}

\frac{d}{d x} (\frac{4 x + a 1 + x}{x ^{2} - 1})

What is the derivative of f(x)=sqrt(x)+x^{2/3}-3x ?
The derivative of f(x)=sqrt(x)+x^{2/3}-3x is 1/(2x^{1/2)}+2/(3x^{1/3)}-3
What is the first derivative of f(x)=sqrt(x)+x^{2/3}-3x ?
The first derivative of f(x)=sqrt(x)+x^{2/3}-3x is 1/(2x^{1/2)}+2/(3x^{1/3)}-3