What is (\partial)/(\partial x)(3y-x/(y^2)) ?

The answer to (\partial)/(\partial x)(3y-x/(y^2)) is -1/(y^2)

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(\partial)/(\partial x)(3y-x/(y^2))

\frac{\partial}{\partial x} (3 y - \frac{x}{y ^{2}})

- \frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (3 y - \frac{x}{y ^{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y) - \frac{\partial}{\partial x} (\frac{x}{y ^{2}})

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (\frac{x}{y ^{2}}) = \frac{1}{y ^{2}}

= 0 - \frac{1}{y ^{2}}

Simplify

= - \frac{1}{y ^{2}}

a re a tan (3 x), 2 sin (3 x), - \frac{π}{9}, \frac{π}{9}

d er i v a t i v e 4 sec^{2} (x)

\int sec^{2} (θ) - 1 d θ

\int e^{x} - \frac{2}{x} d x

\int_{- 3}^{0} (x^{2} - 4 x + 7) d x

What is (\partial)/(\partial x)(3y-x/(y^2)) ?
The answer to (\partial)/(\partial x)(3y-x/(y^2)) is -1/(y^2)