What is the integral from 1 to 2 of 3/(x^4) ?

The integral from 1 to 2 of 3/(x^4) is 7/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 2 of 3/(x^4)

\int_{1}^{2} \frac{3}{x ^{4}} d x

\frac{7}{8}

Decimal

0.875

Solution steps

\int_{1}^{2} \frac{3}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{2} \frac{1}{x ^{4}} d x

Apply the Power Rule

= 3 [- \frac{1}{3 x ^{3}}]_{1}^{2}

Compute the boundaries:

\frac{7}{24}

= 3 \cdot \frac{7}{24}

Simplify

= \frac{7}{8}

\frac{d r}{d θ} = \frac{r ^{2} + 4 r θ}{2 θ ^{2}}

d er i v a t i v e sin (3 x^{2} + 2)

\frac{d}{d z} (\frac{1}{z ^{2}})

d er i v a t i v e ln (1 + e^{- a x})

\int (x + 1) (6 x - 5) d x

What is the integral from 1 to 2 of 3/(x^4) ?
The integral from 1 to 2 of 3/(x^4) is 7/8