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Popular >

y^'= 1/2 y

Solution

y^{^{'}} = \frac{1}{2} y

Solution

y = e^{\frac{t + c _{1}}{2}}

Solution steps

y^{'} (t) = \frac{1}{2} y

Solve separable ODE:

y = e^{\frac{t + c _{1}}{2}}

y = e^{\frac{t + c _{1}}{2}}

Popular Examples

derivative of 4^{cos(3t)}derivative of

4^{c o s (3 t)}

laplacetransform sin(t-pi)laplace transform

sin (t - π)

integral of (3x)/(x^2-x-2)

\int \frac{3 x}{x ^{2} - x - 2} d x

(x-1)dy+(y-x^2+2x^{-3})dx=0

(x - 1) d y + (y - x^{2} + 2 x^{- 3}) d x = 0

area x=y^{1/2},x=2[0,2]area

x = y^{\frac{1}{2}}, x = 2 [0, 2]

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/2 y ?
The solution for y^'= 1/2 y is y=e^{(t+c_{1})/2}