integral from 0 to 4 of (16-x^2)

Lösung

\int_{0}^{4} (16 - x^{2}) d x

\frac{128}{3}

Dezimale

42.66666 \dots

Schritte zur Lösung

\int_{0}^{4} 16 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 16 d x - \int_{0}^{4} x^{2} d x

\int_{0}^{4} 16 d x = 64

\int_{0}^{4} x^{2} d x = \frac{64}{3}

= 64 - \frac{64}{3}

Vereinfache

64 - \frac{64}{3} : \frac{128}{3}

= \frac{128}{3}

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