What is the solution for y^'=5ysin(4x),y(pi/8)=3 ?

The solution for y^'=5ysin(4x),y(pi/8)=3 is y=3e^{-5/4 cos(4x)}

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y^'=5ysin(4x),y(pi/8)=3

y^{^{'}} = 5 y sin (4 x), y (\frac{π}{8}) = 3

y = 3 e^{- \frac{5}{4} c o s (4 x)}

Solution steps

y^{'} (x) = 5 y sin (4 x)

Solve separable ODE:

y = 3 e^{- \frac{5}{4} c o s (4 x)}

y = 3 e^{- \frac{5}{4} c o s (4 x)}

n = 1 \sum \infty \frac{1}{π ^{n}}

x \to 0 lim (x (\frac{1}{2 x}))

t a y l or (x - 4)^{n}, 4

a re a y = cos (x), y = 1 - cos (x), 0 \leq x \leq π

\int \frac{24}{1 + 25 r ^{2}} d r

What is the solution for y^'=5ysin(4x),y(pi/8)=3 ?
The solution for y^'=5ysin(4x),y(pi/8)=3 is y=3e^{-5/4 cos(4x)}