(\partial)/(\partial y)(2x+3y-7)

解

\frac{\partial}{\partial y} (2 x + 3 y - 7)

3

解答ステップ

\frac{\partial}{\partial y} (2 x + 3 y - 7)

x

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (3 y) - \frac{\partial}{\partial y} (7)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (7) = 0

= 0 + 3 - 0

簡素化

= 3