derivative f(x)=(x^3)/3+x^2+4x-10

Lösung

ableitung von

f (x) = \frac{x ^{3}}{3} + x^{2} + 4 x - 10

x^{2} + 2 x + 4

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} + x^{2} + 4 x - 10)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (10)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (10) = 0

= x^{2} + 2 x + 4 - 0

Vereinfache

= x^{2} + 2 x + 4

t an g e n t y = 10 x - x^{2}, (5, 26)

\int \frac{1}{x - ln ^{2} ( x ) + ln ( x ) + 3} d x

\int \frac{2 x + 5}{9 - x ^{2}} d x

d er i v a t i v e y = sin (e^{2 x})

\frac{d}{d x} (\frac{x + 3}{8 x ^{2} e ^{x}})