斜率 (-1/2 ,7),(1,-1)

解答

斜率

(- \frac{1}{2}, 7), (1, - 1)

m = - \frac{16}{3}

求解步骤

两点之间的斜率: 斜率

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (- \frac{1}{2}, 7), (x_{2}, y_{2}) = (1, - 1)

m = \frac{- 1 - 7}{1 - ( - \frac{1}{2} )}

整理后得

m = - \frac{16}{3}

e^{- y} cos (x) + \frac{d y}{d x} sin^{2} (x) = 0

\frac{d}{d x} ((4 x - 3)^{2 x + 1})

x \to - 7 lim (\frac{x ^{2} - 9}{7 - x})

\int \frac{1}{x 4 x ^{2} - 1} d x

x \to 1 + lim (arctan (ln (x - 1)))