(\partial)/(\partial x)(cos^2(2x))

解答

\frac{\partial}{\partial x} (cos^{2} (2 x))

- 2 sin (4 x)

求解步骤

\frac{\partial}{\partial x} (cos^{2} (2 x))

使用连锁律:

2 cos (2 x) \frac{\partial}{\partial x} (cos (2 x))

= 2 cos (2 x) \frac{\partial}{\partial x} (cos (2 x))

\frac{\partial}{\partial x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 cos (2 x) (- sin (2 x) \cdot 2)

化简

2 cos (2 x) (- sin (2 x) \cdot 2) : - 2 sin (4 x)

= - 2 sin (4 x)

t an g e n t f (x) = 4 x^{2} + 2 x, at x = 2

\int x^{3} cos (x^{4} + 2) d x

\frac{d}{d x} (2 x + 7 + \frac{450}{x})

d er i v a t i v e f (x) = \frac{2}{3} (x^{2} + 1)^{\frac{3}{2}}

y^{^{''}} + y = 0, y (\frac{π}{3}) = 0, y^{^{'}} (\frac{π}{3}) = 6