What is the derivative of ln(8x+5) ?

The derivative of ln(8x+5) is 8/(8x+5)

What is the first derivative of ln(8x+5) ?

The first derivative of ln(8x+5) is 8/(8x+5)

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derivative of

ln (8 x + 5)

\frac{8}{8 x + 5}

Solution steps

\frac{d}{d x} (ln (8 x + 5))

Apply the chain rule:

\frac{1}{8 x + 5} \frac{d}{d x} (8 x + 5)

= \frac{1}{8 x + 5} \frac{d}{d x} (8 x + 5)

\frac{d}{d x} (8 x + 5) = 8

= \frac{1}{8 x + 5} \cdot 8

Simplify

\frac{1}{8 x + 5} \cdot 8 : \frac{8}{8 x + 5}

= \frac{8}{8 x + 5}

x y^{^{'}} + 9 y = 12 y^{2}, y (1) = - 1

\int \frac{2 x + 1}{x ^{2} - x} d x

\frac{d}{d t} (\frac{3 y ^{2} - t ^{2}}{y ^{5}})

\frac{d}{d x} (ln (\frac{4}{x x + 1}))

\frac{\partial}{\partial x} (- 2 x y)

What is the derivative of ln(8x+5) ?
The derivative of ln(8x+5) is 8/(8x+5)
What is the first derivative of ln(8x+5) ?
The first derivative of ln(8x+5) is 8/(8x+5)