What is the solution for (2x^2+y^2)dx-x^2dy=0 ?

The solution for (2x^2+y^2)dx-x^2dy=0 is y=(sqrt(7)xtan((sqrt(7)(ln(x)+c_{1}))/2))/(2)+1/2 x

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(2x^2+y^2)dx-x^2dy=0

(2 x^{2} + y^{2}) d x - x^{2} d y = 0

y = \frac{7 x tan ( \frac{7 ( l n ( x ) + c _{1} )}{2} )}{2} + \frac{1}{2} x

Solution steps

(2 x^{2} + y^{2}) d x - x^{2} d y = 0

Solve using substitution:

y = \frac{7 x tan ( \frac{7 ( l n ( x ) + c _{1} )}{2} )}{2} + \frac{1}{2} x

y = \frac{7 x tan ( \frac{7 ( l n ( x ) + c _{1} )}{2} )}{2} + \frac{1}{2} x

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What is the solution for (2x^2+y^2)dx-x^2dy=0 ?
The solution for (2x^2+y^2)dx-x^2dy=0 is y=(sqrt(7)xtan((sqrt(7)(ln(x)+c_{1}))/2))/(2)+1/2 x