integral de 1/(x-sqrt(1-x^2))

Solución

\int \frac{1}{x - 1 - x ^{2}} d x

\frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 2 tan (\frac{1}{2} arcsin (x)) - 1 - \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 1 - arctan (tan (\frac{1}{2} arcsin (x))) + C

Pasos de solución

\int \frac{1}{x - 1 - x ^{2}} d x

Aplicar integración por sustitución trigonométrica

: \int \frac{cos ( u )}{sin ( u ) - cos ( u )} d u

= \int \frac{cos ( u )}{sin ( u ) - cos ( u )} d u

Aplicar integración por sustitución

: \int \frac{2 ( 1 - v ^{2} )}{( 2 v - 1 + v ^{2} ) ( 1 + v ^{2} )} d v

= \int \frac{2 ( 1 - v ^{2} )}{( 2 v - 1 + v ^{2} ) ( 1 + v ^{2} )} d v

Sacar la constante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1 - v ^{2}}{( 2 v - 1 + v ^{2} ) ( 1 + v ^{2} )} d v

Tomar la fracción parcial de

\frac{1 - v ^{2}}{( 2 v - 1 + v ^{2} ) ( 1 + v ^{2} )} : \frac{v + 1}{2 ( v ^{2} + 2 v - 1 )} + \frac{- v - 1}{2 ( v ^{2} + 1 )}

= 2 \cdot \int \frac{v + 1}{2 ( v ^{2} + 2 v - 1 )} + \frac{- v - 1}{2 ( v ^{2} + 1 )} d v

Aplicar la regla de la suma:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int \frac{v + 1}{2 ( v ^{2} + 2 v - 1 )} d v + \int \frac{- v - 1}{2 ( v ^{2} + 1 )} d v)

\int \frac{v + 1}{2 ( v ^{2} + 2 v - 1 )} d v = \frac{1}{4} ln v^{2} + 2 v - 1

\int \frac{- v - 1}{2 ( v ^{2} + 1 )} d v = \frac{1}{2} (- \frac{1}{2} ln v^{2} + 1 - arctan (v))

= 2 (\frac{1}{4} ln v^{2} + 2 v - 1 + \frac{1}{2} (- \frac{1}{2} ln v^{2} + 1 - arctan (v)))

Sustitución hacia atrás

= 2 (\frac{1}{4} ln tan^{2} (\frac{arcsin ( x )}{2}) + 2 tan (\frac{arcsin ( x )}{2}) - 1 + \frac{1}{2} (- \frac{1}{2} ln tan^{2} (\frac{arcsin ( x )}{2}) + 1 - arctan (tan (\frac{arcsin ( x )}{2}))))

Simplificar

2 (\frac{1}{4} ln tan^{2} (\frac{arcsin ( x )}{2}) + 2 tan (\frac{arcsin ( x )}{2}) - 1 + \frac{1}{2} (- \frac{1}{2} ln tan^{2} (\frac{arcsin ( x )}{2}) + 1 - arctan (tan (\frac{arcsin ( x )}{2})))) : \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 2 tan (\frac{1}{2} arcsin (x)) - 1 - \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 1 - arctan (tan (\frac{1}{2} arcsin (x)))

= \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 2 tan (\frac{1}{2} arcsin (x)) - 1 - \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 1 - arctan (tan (\frac{1}{2} arcsin (x)))

Agregar una constante a la solución

= \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 2 tan (\frac{1}{2} arcsin (x)) - 1 - \frac{1}{2} ln tan^{2} (\frac{1}{2} arcsin (x)) + 1 - arctan (tan (\frac{1}{2} arcsin (x))) + C

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