What is the integral of ((3x+3)/(x^2+8x+16)) ?

The integral of ((3x+3)/(x^2+8x+16)) is 3ln|x+4|+9/(x+4)+C

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integral of ((3x+3)/(x^2+8x+16))

\int (\frac{3 x + 3}{x ^{2} + 8 x + 16}) d x

3 ln ∣ x + 4 ∣ + \frac{9}{x + 4} + C

Solution steps

\int \frac{3 x + 3}{x ^{2} + 8 x + 16} d x

Expand

\frac{3 x + 3}{x ^{2} + 8 x + 16} : \frac{3 x}{x ^{2} + 8 x + 16} + \frac{3}{x ^{2} + 8 x + 16}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x}{x ^{2} + 8 x + 16} d x + \int \frac{3}{x ^{2} + 8 x + 16} d x

\int \frac{3 x}{x ^{2} + 8 x + 16} d x = 3 (ln ∣ x + 4 ∣ + \frac{4}{x + 4})

\int \frac{3}{x ^{2} + 8 x + 16} d x = - \frac{3}{x + 4}

= 3 (ln ∣ x + 4 ∣ + \frac{4}{x + 4}) - \frac{3}{x + 4}

Simplify

3 (ln ∣ x + 4 ∣ + \frac{4}{x + 4}) - \frac{3}{x + 4} : 3 ln ∣ x + 4 ∣ + \frac{9}{x + 4}

= 3 ln ∣ x + 4 ∣ + \frac{9}{x + 4}

Add a constant to the solution

= 3 ln ∣ x + 4 ∣ + \frac{9}{x + 4} + C

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What is the integral of ((3x+3)/(x^2+8x+16)) ?
The integral of ((3x+3)/(x^2+8x+16)) is 3ln|x+4|+9/(x+4)+C