What is the integral of (8x^3-9x^2+10) ?

The integral of (8x^3-9x^2+10) is 2x^4-3x^3+10x+C

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integral of (8x^3-9x^2+10)

\int (8 x^{3} - 9 x^{2} + 10) d x

2 x^{4} - 3 x^{3} + 10 x + C

Solution steps

\int 8 x^{3} - 9 x^{2} + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{3} d x - \int 9 x^{2} d x + \int 10 d x

\int 8 x^{3} d x = 2 x^{4}

\int 9 x^{2} d x = 3 x^{3}

\int 10 d x = 10 x

= 2 x^{4} - 3 x^{3} + 10 x

Add a constant to the solution

= 2 x^{4} - 3 x^{3} + 10 x + C

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What is the integral of (8x^3-9x^2+10) ?
The integral of (8x^3-9x^2+10) is 2x^4-3x^3+10x+C