integral of 6/((x-9)(x-3))

Lösung

\int \frac{6}{( x - 9 ) ( x - 3 )} d x

ln ∣ x - 9 ∣ - ln ∣ x - 3 ∣ + C

Schritte zur Lösung

\int \frac{6}{( x - 9 ) ( x - 3 )} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{1}{( x - 9 ) ( x - 3 )} d x

Ermittle den Partialbruch von

\frac{1}{( x - 9 ) ( x - 3 )} : \frac{1}{6 ( x - 9 )} - \frac{1}{6 ( x - 3 )}

= 6 \cdot \int \frac{1}{6 ( x - 9 )} - \frac{1}{6 ( x - 3 )} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int \frac{1}{6 ( x - 9 )} d x - \int \frac{1}{6 ( x - 3 )} d x)

\int \frac{1}{6 ( x - 9 )} d x = \frac{1}{6} ln ∣ x - 9 ∣

\int \frac{1}{6 ( x - 3 )} d x = \frac{1}{6} ln ∣ x - 3 ∣

= 6 (\frac{1}{6} ln ∣ x - 9 ∣ - \frac{1}{6} ln ∣ x - 3 ∣)

Vereinfache

6 (\frac{1}{6} ln ∣ x - 9 ∣ - \frac{1}{6} ln ∣ x - 3 ∣) : ln ∣ x - 9 ∣ - ln ∣ x - 3 ∣

= ln ∣ x - 9 ∣ - ln ∣ x - 3 ∣

Füge eine Konstante zur Lösung hinzu

= ln ∣ x - 9 ∣ - ln ∣ x - 3 ∣ + C

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