What is the integral of 24x^3-15x^2+8x ?

The integral of 24x^3-15x^2+8x is 6x^4-5x^3+4x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 24x^3-15x^2+8x

\int 24 x^{3} - 15 x^{2} + 8 x d x

6 x^{4} - 5 x^{3} + 4 x^{2} + C

Solution steps

\int 24 x^{3} - 15 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 24 x^{3} d x - \int 15 x^{2} d x + \int 8 x d x

\int 24 x^{3} d x = 6 x^{4}

\int 15 x^{2} d x = 5 x^{3}

\int 8 x d x = 4 x^{2}

= 6 x^{4} - 5 x^{3} + 4 x^{2}

Add a constant to the solution

= 6 x^{4} - 5 x^{3} + 4 x^{2} + C

\int \frac{cos ( 3 x )}{sin ^{3} ( 3 x )} d x

\int 2 cos^{2} (t) d t

\int (t^{2} - cos (t)) d t

\int \frac{2}{4 - 2 x} d x

\int \frac{1}{π} x sin (x) d x

What is the integral of 24x^3-15x^2+8x ?
The integral of 24x^3-15x^2+8x is 6x^4-5x^3+4x^2+C