derivative of ln(1+8x)

解答

\frac{d}{d x} (ln (1 + 8 x))

\frac{8}{1 + 8 x}

求解步骤

\frac{d}{d x} (ln (1 + 8 x))

使用连锁律:

\frac{1}{1 + 8 x} \frac{d}{d x} (1 + 8 x)

= \frac{1}{1 + 8 x} \frac{d}{d x} (1 + 8 x)

\frac{d}{d x} (1 + 8 x) = 8

= \frac{1}{1 + 8 x} \cdot 8

化简

\frac{1}{1 + 8 x} \cdot 8 : \frac{8}{1 + 8 x}

= \frac{8}{1 + 8 x}

x \to 1 + lim (\frac{1}{x ^{2} + 1})

\frac{\partial}{\partial y} (e^{x e^{y}})

\int (1 - y^{2}) d y

y^{^{''}} + 7 y^{^{'}} + 10 y = - 18 t e^{2 t}

x \to 0 lim (\frac{0}{x ^{2}})