What is the integral of cos(t/4) ?

The integral of cos(t/4) is 4sin(t/4)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of cos(t/4)

\int cos (\frac{t}{4}) d t

4 sin (\frac{t}{4}) + C

Solution steps

\int cos (\frac{t}{4}) d t

Apply u-substitution

= \int cos (u) \cdot 4 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 4 sin (u)

Substitute back

u = \frac{t}{4}

= 4 sin (\frac{t}{4})

Add a constant to the solution

= 4 sin (\frac{t}{4}) + C

\int \frac{6}{x ln ^{3} ( 4 x )} d x

\int 12 (x^{4} + 4 x^{2} + 1)^{2} (x^{3} + 2 x) d x

\int 12 x^{11} d x

in t e g r a l rr θ \cdot 2 - 4 sin (θ)

\int \frac{1}{x + 3 x ^{2}} d x