tangent y=1.1x+e^x,(0,1)

解答

切线

y = 1.1 x + e^{x}, (0, 1)

y = 2.1 x + 1

求解步骤

计算

y = 1.1 x + e^{x}

的斜率:

\frac{d y}{d x} = 1.1 + e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2.1

找到斜率 m=

2.1

且穿过

(0, 1)

的直线:

y = 2.1 x + 1

y = 2.1 x + 1

v o l u m e ab o u t y = 0, y = x^{2}, y = 4 x - x^{2}, [0, 2]

(1 + cos (t)) y^{^{'}} = (1 + e^{- y}) sin (t), y (0) = 0

d er i v a t i v e (x^{2} + 5) (8 - x)

\int \frac{2 x}{1 + 4 x ^{2}} d x

d er i v a t i v e \frac{6}{x ^{3}}