y^{''}+289y=sec(17x)

Lösung

y^{^{''}} + 289 y = sec (17 x)

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{1}{289} ln (cos (17 x)) cos (17 x) + \frac{1}{17} x sin (17 x)

Schritte zur Lösung

y^{''} (x) + 289 y = sec (17 x)

Solve linear ODE:

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{1}{289} ln (cos (17 x)) cos (17 x) + \frac{1}{17} x sin (17 x)

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{1}{289} ln (cos (17 x)) cos (17 x) + \frac{1}{17} x sin (17 x)

d er i v a t i v e f (x) = 2 x^{5} - 3 e^{6 x}

\int_{0}^{1} x^{2} - x d x

t an g e n t - 2 x^{5} + 4 x^{4}

\frac{d}{d x} (\frac{12}{x} - \frac{4}{x ^{3}} + \frac{1}{x ^{4}})

y^{^{''}} + 2 y^{^{'}} + y = 0, y (2) = 1, y^{^{'}} (2) = - 2