derivative f(x)=2x^5-3e^{6x}

Lösung

ableitung von

f (x) = 2 x^{5} - 3 e^{6 x}

10 x^{4} - 18 e^{6 x}

Schritte zur Lösung

\frac{d}{d x} (2 x^{5} - 3 e^{6 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{5}) - \frac{d}{d x} (3 e^{6 x})

\frac{d}{d x} (2 x^{5}) = 10 x^{4}

\frac{d}{d x} (3 e^{6 x}) = 18 e^{6 x}

= 10 x^{4} - 18 e^{6 x}

\int_{0}^{1} x^{2} - x d x

t an g e n t - 2 x^{5} + 4 x^{4}

\frac{d}{d x} (\frac{12}{x} - \frac{4}{x ^{3}} + \frac{1}{x ^{4}})

y^{^{''}} + 2 y^{^{'}} + y = 0, y (2) = 1, y^{^{'}} (2) = - 2

\int \frac{( x ^{2} - x + 1 )}{( x ^{2} + x )} d x