What is the integral of (-9ln(x))/x ?

The integral of (-9ln(x))/x is -9/2 ln^2(x)+C

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integral of (-9ln(x))/x

\int \frac{- 9 ln ( x )}{x} d x

- \frac{9}{2} ln^{2} (x) + C

Solution steps

\int \frac{- 9 ln ( x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int \frac{ln ( x )}{x} d x

Apply u-substitution

: \int u d u

= - 9 \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= - 9 \cdot \frac{u ^{2}}{2}

Substitute back

u = ln (x)

= - 9 \cdot \frac{ln ^{2} ( x )}{2}

Simplify

- 9 \cdot \frac{ln ^{2} ( x )}{2} : - \frac{9}{2} ln^{2} (x)

= - \frac{9}{2} ln^{2} (x)

Add a constant to the solution

= - \frac{9}{2} ln^{2} (x) + C

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What is the integral of (-9ln(x))/x ?
The integral of (-9ln(x))/x is -9/2 ln^2(x)+C