What is the integral of (x+3)/(x^3+x) ?

The integral of (x+3)/(x^3+x) is 3ln|x|-3/2 ln|x^2+1|+arctan(x)+C

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integral of (x+3)/(x^3+x)

\int \frac{x + 3}{x ^{3} + x} d x

3 ln ∣ x ∣ - \frac{3}{2} ln x^{2} + 1 + arctan (x) + C

Solution steps

\int \frac{x + 3}{x ^{3} + x} d x

Take the partial fraction of

\frac{x + 3}{x ^{3} + x} : \frac{3}{x} + \frac{- 3 x + 1}{x ^{2} + 1}

= \int \frac{3}{x} + \frac{- 3 x + 1}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x} d x + \int \frac{- 3 x + 1}{x ^{2} + 1} d x

\int \frac{3}{x} d x = 3 ln ∣ x ∣

\int \frac{- 3 x + 1}{x ^{2} + 1} d x = - \frac{3}{2} ln x^{2} + 1 + arctan (x)

= 3 ln ∣ x ∣ - \frac{3}{2} ln x^{2} + 1 + arctan (x)

Add a constant to the solution

= 3 ln ∣ x ∣ - \frac{3}{2} ln x^{2} + 1 + arctan (x) + C

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What is the integral of (x+3)/(x^3+x) ?
The integral of (x+3)/(x^3+x) is 3ln|x|-3/2 ln|x^2+1|+arctan(x)+C