What is the integral of (7+tan^2(θ)) ?

The integral of (7+tan^2(θ)) is 6θ+tan(θ)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (7+tan^2(θ))

\int (7 + tan^{2} (θ)) d θ

6 θ + tan (θ) + C

Solution steps

\int 7 + tan^{2} (θ) d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 d θ + \int tan^{2} (θ) d θ

\int 7 d θ = 7 θ

\int tan^{2} (θ) d θ = - θ + tan (θ)

= 7 θ - θ + tan (θ)

Simplify

= 6 θ + tan (θ)

Add a constant to the solution

= 6 θ + tan (θ) + C

\int \frac{x ^{3} + 2 x ^{2} - 7 x}{x} d x

\int x (x + 1) d x

\int \frac{2 x + 1}{x ^{2} - 5 x + 6} d x

\int (sin (x)) e^{- s x}

\int \frac{1}{2 x x + 1} d x

What is the integral of (7+tan^2(θ)) ?
The integral of (7+tan^2(θ)) is 6θ+tan(θ)+C