integral of (3cos(x)+2sec(x)tan(x))

Lösung

\int (3 cos (x) + 2 sec (x) tan (x)) d x

3 sin (x) + 2 sec (x) + C

Schritte zur Lösung

\int 3 cos (x) + 2 sec (x) tan (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 cos (x) d x + \int 2 sec (x) tan (x) d x

\int 3 cos (x) d x = 3 sin (x)

\int 2 sec (x) tan (x) d x = 2 sec (x)

= 3 sin (x) + 2 sec (x)

Füge eine Konstante zur Lösung hinzu

= 3 sin (x) + 2 sec (x) + C

\int \frac{x ^{3} + 2 x - 1}{( x - 3 ) ^{3}} d x

\int \frac{4 x ^{3}}{x ^{2} - 9} d x

\int (x - 2)^{- \frac{1}{2}} d x

\int \frac{cos ( x )}{2 sin ( x ) - 1} d x

\int \frac{x ^{3}}{( 9 ) ^{2} - x ^{2}} d x