integral of (x-3)/(x^2+9)

Lösung

\int \frac{x - 3}{x ^{2} + 9} d x

\frac{1}{2} ln x^{2} + 9 - arctan (\frac{x}{3}) + C

Schritte zur Lösung

\int \frac{x - 3}{x ^{2} + 9} d x

Multipliziere aus

\frac{x - 3}{x ^{2} + 9} : \frac{x}{x ^{2} + 9} - \frac{3}{x ^{2} + 9}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 9} d x - \int \frac{3}{x ^{2} + 9} d x

\int \frac{x}{x ^{2} + 9} d x = \frac{1}{2} ln x^{2} + 9

\int \frac{3}{x ^{2} + 9} d x = arctan (\frac{x}{3})

= \frac{1}{2} ln x^{2} + 9 - arctan (\frac{x}{3})

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} ln x^{2} + 9 - arctan (\frac{x}{3}) + C

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