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人気のある微分積分 >

derivative sqrt(t^2+1)

解

導関数

t^{2} + 1

解

\frac{t}{t ^{2} + 1}

解答ステップ

\frac{d}{d t} (t^{2} + 1)

連鎖法則を適用:

\frac{1}{2 t ^{2} + 1} \frac{d}{d t} (t^{2} + 1)

= \frac{1}{2 t ^{2} + 1} \frac{d}{d t} (t^{2} + 1)

\frac{d}{d t} (t^{2} + 1) = 2 t

= \frac{1}{2 t ^{2} + 1} \cdot 2 t

簡素化

\frac{1}{2 t ^{2} + 1} \cdot 2 t : \frac{t}{t ^{2} + 1}

= \frac{t}{t ^{2} + 1}

グラフ

人気の例

derivative of 5+3sqrt(x)

\frac{d}{d x} (5 + 3 x)

integral of (5x-3)/(x^2+4)

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\int \frac{1}{x ^{2} + 4 x + 13} d x

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x \to π lim (ln ∣ cos (x) - 7 ∣)

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