integral from 0 to pi/2 of cos(θ)sin(θ)

Lösung

\int_{0}^{\frac{π}{2}} cos (θ) sin (θ) d θ

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} cos (θ) sin (θ) d θ

Wende U-Substitution an

= \int_{0}^{1} u d u

Wende die Potenzregel an

= [\frac{u ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{2}

\int_{- 1}^{1} x cos (x) d x

\int_{0}^{π} x^{2} d x

\int_{0}^{π} cos^{2} (θ) sin (θ) d θ

\int_{0}^{π} sin (x) sin (x) d x

\int_{- 1}^{2} x^{2} - x d x