integral from 0 to 1 of 1/(sqrt(1-t^2))

Lösung

\int_{0}^{1} \frac{1}{1 - t ^{2}} d t

\frac{π}{2}

Dezimale

1.57079 \dots

Schritte zur Lösung

\int_{0}^{1} \frac{1}{1 - t ^{2}} d t

Nutze das gemeinsame Integral :

\int \frac{1}{1 - t ^{2}} d t = arcsin (t)

= [arcsin (t)]_{0}^{1}

Berechne die Grenzen:

\frac{π}{2}

= \frac{π}{2}

\int_{0}^{π} sin (t) cos (t) d t

\int_{0}^{1} (e^{x} + 1) d x

\int_{2}^{5} (6 + cos (\frac{x}{10})) d x

\int_{0}^{1} 2 x^{3} d x

\int_{2}^{4} x^{2} - 2 x - 3 d x