What is the integral from 0 to 1 of x^1ln(x) ?

The integral from 0 to 1 of x^1ln(x) is -1/4

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integral from 0 to 1 of x^1ln(x)

\int_{0}^{1} x^{1} ln (x) d x

- \frac{1}{4}

Decimal

- 0.25

Solution steps

\int_{0}^{1} x^{1} ln (x) d x

Simplify

= \int_{0}^{1} x ln (x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x]_{0}^{1}

= [\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x]_{0}^{1}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= [\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}]_{0}^{1}

Compute the boundaries:

- \frac{1}{4}

= - \frac{1}{4}

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What is the integral from 0 to 1 of x^1ln(x) ?
The integral from 0 to 1 of x^1ln(x) is -1/4