integral from 0 to 3 of (-x^2+3x)

Lösung

\int_{0}^{3} (- x^{2} + 3 x) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{0}^{3} - x^{2} + 3 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 3 x d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 3 x d x = \frac{27}{2}

= - 9 + \frac{27}{2}

Vereinfache

- 9 + \frac{27}{2} : \frac{9}{2}

= \frac{9}{2}

\int_{0}^{\frac{π}{6}} sin (x) d x

\int_{0}^{x} t^{2} d t

\int_{0}^{2} \frac{x}{x ^{2} + 5} d x

\int_{0}^{2} t^{3} 9 t^{4} + 1 d t

\int_{\frac{π}{2}}^{π} cos (x) + 2 d x