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人気のある微分積分 >

integral from-1 to 2 of (x^3-4x)

解

\int_{- 1}^{2} (x^{3} - 4 x) d x

解

- \frac{9}{4}

+1

十進法表記

- 2.25

解答ステップ

\int_{- 1}^{2} x^{3} - 4 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x - \int_{- 1}^{2} 4 x d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} 4 x d x = 6

= \frac{15}{4} - 6

簡素化

\frac{15}{4} - 6 : - \frac{9}{4}

= - \frac{9}{4}

グラフ

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