integral from 0 to 4 of (x^2-2x)

Lösung

\int_{0}^{4} (x^{2} - 2 x) d x

\frac{16}{3}

Dezimale

5.33333 \dots

Schritte zur Lösung

\int_{0}^{4} x^{2} - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 x d x = 16

= \frac{64}{3} - 16

Vereinfache

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

\int_{0}^{3} e^{3 x} d x

\int_{1}^{4} x 3 - x d x

\int_{x}^{0} t^{2} + 4 d t

\int_{\frac{π}{6}}^{\frac{π}{3}} csc^{3} (x) d x

\int_{0}^{4} 4 x - x^{2} d x