integral from-1 to 1 of (4-9y)

Lösung

\int_{- 1}^{1} (4 - 9 y) d y

8

Schritte zur Lösung

\int_{- 1}^{1} 4 - 9 y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 4 d y - \int_{- 1}^{1} 9 y d y

\int_{- 1}^{1} 4 d y = 8

\int_{- 1}^{1} 9 y d y = 0

= 8 - 0

Vereinfache

= 8

\int_{0}^{1} e^{x} x d x

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