integral from 1 to 6 of 2^x

Lösung

\int_{1}^{6} 2^{x} d x

\frac{62}{ln ( 2 )}

Dezimale

89.44709 \dots

Schritte zur Lösung

\int_{1}^{6} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{1}^{6}

Berechne die Grenzen:

\frac{62}{ln ( 2 )}

= \frac{62}{ln ( 2 )}

\int_{2}^{3} x e^{2 x} d x

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