What is the integral from 0 to x of 2ze^{-x^2} ?

The integral from 0 to x of 2ze^{-x^2} is 2zxe^{-x^2}

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integral from 0 to x of 2ze^{-x^2}

\int_{0}^{x} 2 z e^{- x^{2}} d y

2 z x e^{- x^{2}}

Solution steps

\int_{0}^{x} 2 z e^{- x^{2}} d y

Integral of a constant:

\int a d x = a x

= [2 z e^{- x^{2}} y]_{0}^{x}

Compute the boundaries:

2 z x e^{- x^{2}}

= 2 z x e^{- x^{2}}

\int_{0}^{4} - 2 x^{2} + 8 x d x

\int_{0}^{\frac{π}{3}} \frac{x}{cos ^{2} ( x )} d x

\int_{0}^{4} 4 x^{2} d x

\int_{- 7}^{7} x^{2} - 36 d x

\int_{0}^{2} (- 4 x^{4} + 8 x^{3}) d x

What is the integral from 0 to x of 2ze^{-x^2} ?
The integral from 0 to x of 2ze^{-x^2} is 2zxe^{-x^2}