integral from 8 to 17 of xsqrt(x^2-64)

Lösung

\int_{8}^{17} x x^{2} - 64 d x

1125

Schritte zur Lösung

\int_{8}^{17} x x^{2} - 64 d x

Wende U-Substitution an

= \int_{0}^{15} u^{2} d u

Wende die Potenzregel an

= [\frac{u ^{3}}{3}]_{0}^{15}

Berechne die Grenzen:

1125

= 1125

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