integral from 1 to 4 of x^2+4x+5

Lösung

\int_{1}^{4} x^{2} + 4 x + 5 d x

66

Schritte zur Lösung

\int_{1}^{4} x^{2} + 4 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} 4 x d x + \int_{1}^{4} 5 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 4 x d x = 30

\int_{1}^{4} 5 d x = 15

= 21 + 30 + 15

Vereinfache

= 66

\int_{0}^{1} x^{2} - 4 x + 3 d x

\int_{0}^{y} e^{y^{2}} d y

\int_{5}^{8} 3 x + 1 d x

\int_{6}^{7} \frac{1}{x ^{2}} d x

\int_{4}^{2} g (x) d x