integral from 0 to 2 of 2x+1

Lösung

\int_{0}^{2} 2 x + 1 d x

6

Schritte zur Lösung

\int_{0}^{2} 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 4 + 2

Vereinfache

= 6

\int_{2}^{5} 4 x d x

\int_{- 2}^{2} (x - 1) 4 - x^{2} d x

\int_{0}^{0.5} sin (x) d x

\int_{y}^{2 y} (10 + 2 x^{2} + 2 y^{2}) d x

\int_{1}^{5} \frac{2 ln ( x )}{x} d x