integral from-1 to 1 of 1+sqrt(1-x^2)

Lösung

\int_{- 1}^{1} 1 + 1 - x^{2} d x

2 + \frac{π}{2}

Dezimale

3.57079 \dots

Schritte zur Lösung

\int_{- 1}^{1} 1 + 1 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} 1 - x^{2} d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} 1 - x^{2} d x = \frac{π}{2}

= 2 + \frac{π}{2}

\int_{1}^{e} 2 π x ln (x) d x

\int_{0}^{1} 1 - x^{2} x d x

\int_{0}^{0.5} 3 x^{2} d x

\int_{- 1}^{1} x e^{- x} d x

\int_{1}^{7} (2 x + \frac{1}{x}) d x