integral from-1 to 1 of (x+sqrt(1-x^2))

Lösung

\int_{- 1}^{1} (x + 1 - x^{2}) d x

\frac{π}{2}

Dezimale

1.57079 \dots

Schritte zur Lösung

\int_{- 1}^{1} x + 1 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x d x + \int_{- 1}^{1} 1 - x^{2} d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 - x^{2} d x = \frac{π}{2}

= 0 + \frac{π}{2}

Vereinfache

= \frac{π}{2}

\int_{0}^{l n (x)} e^{x} - 1 d x

\int_{0}^{1} 4 d x

\int_{0}^{\frac{π}{2}} cos (t) sin (t) d t

\int_{- 3}^{3} 2 x d x

\int_{0}^{1} 4 x^{9} + 8 x^{5} - 5 x^{3} - 6 d x