integral from 0 to 1 of t^4

Lösung

\int_{0}^{1} t^{4} d t

\frac{1}{5}

Dezimale

0.2

Schritte zur Lösung

\int_{0}^{1} t^{4} d t

Wende die Potenzregel an

= [\frac{t ^{5}}{5}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{5}

= \frac{1}{5}

\int_{0}^{4} (4 t - 1)^{2} d t

\int_{- 1}^{4} (x + 4) - (x^{2} - 2 x) d x

\int_{0}^{1} x^{\frac{5}{6}} d x

\int_{0}^{1} (x + 2 1 - x^{2}) d x

\int_{0}^{1} \frac{1}{4 + 5 x - 1} d x