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人気のある微分積分 >

integral from 0 to 4 of (6x+sqrt(x))

解

\int_{0}^{4} (6 x + x) d x

解

\frac{160}{3}

+1

十進法表記

53.33333 \dots

解答ステップ

\int_{0}^{4} 6 x + x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 6 x d x + \int_{0}^{4} x d x

\int_{0}^{4} 6 x d x = 48

\int_{0}^{4} x d x = \frac{16}{3}

= 48 + \frac{16}{3}

簡素化

48 + \frac{16}{3} : \frac{160}{3}

= \frac{160}{3}

グラフ

人気の例

integral from 0 to 1 of x^2-2x+3

\int_{0}^{1} x^{2} - 2 x + 3 d x

integral from 1 to 3 of 4/x

\int_{1}^{3} \frac{4}{x} d x

integral from 1 to 2 of (10-5x)/(x^3)

\int_{1}^{2} \frac{10 - 5 x}{x ^{3}} d x

integral from 0 to 1 of 3y^2(e^{y^3}-1)

\int_{0}^{1} 3 y^{2} (e^{y^{3}} - 1) d y

integral from-2 to 2 of 4x^2-x^4

\int_{- 2}^{2} 4 x^{2} - x^{4} d x