integral from 2 to 5 of 2000x+1000

Lösung

\int_{2}^{5} 2000 x + 1000 d x

24000

Schritte zur Lösung

\int_{2}^{5} 2000 x + 1000 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} 2000 x d x + \int_{2}^{5} 1000 d x

\int_{2}^{5} 2000 x d x = 21000

\int_{2}^{5} 1000 d x = 3000

= 21000 + 3000

Vereinfache

= 24000

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