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integral de 0 a pi/4 de sqrt(tan(x))

Solución

\int_{0}^{\frac{π}{4}} tan (x) d x

\frac{2 ln ( 2 - 2 ) + 4 arctan ( 1 + 2 ) + 4 arctan ( 2 - 1 ) - 2 ln ( 2 + 2 )}{4 2}

Notación decimal

0.48749 \dots

Pasos de solución

\int_{0}^{\frac{π}{4}} tan (x) d x

Aplicar integración por sustitución trigonométrica

: \int_{0}^{1} \frac{u}{1 + u ^{2}} d u

= \int_{0}^{1} \frac{u}{1 + u ^{2}} d u

Aplicar integración por sustitución

= \int_{0}^{2} \frac{2 v}{4 + v ^{2}} d v

Sacar la constante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2} \frac{v}{4 + v ^{2}} d v

Aplicar integración por sustitución

: \int_{0}^{2} \frac{2 w ^{2}}{4 + w ^{4}} d w

= 2 \cdot \int_{0}^{2} \frac{2 w ^{2}}{4 + w ^{4}} d w

Sacar la constante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot 2 \cdot \int_{0}^{2} \frac{w ^{2}}{4 + w ^{4}} d w

Tomar la fracción parcial de

\frac{w ^{2}}{4 + w ^{4}} : - \frac{w}{4 ( w ^{2} + 2 w + 2 )} + \frac{w}{4 ( w ^{2} - 2 w + 2 )}

= 2 \cdot 2 \cdot \int_{0}^{2} - \frac{w}{4 ( w ^{2} + 2 w + 2 )} + \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w

Aplicar la regla de la suma:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 \cdot 2 (- \int_{0}^{2} \frac{w}{4 ( w ^{2} + 2 w + 2 )} d w + \int_{0}^{2} \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w)

\int_{0}^{2} \frac{w}{4 ( w ^{2} + 2 w + 2 )} d w = \frac{1}{4} (\frac{1}{2} ln (2 + 2) - arctan (2 + 1) + \frac{π}{4})

\int_{0}^{2} \frac{w}{4 ( w ^{2} - 2 w + 2 )} d w = \frac{1}{4} (\frac{1}{2} ln (2 - 2) + arctan (2 - 1) + \frac{π}{4})

= 2 \cdot 2 (- \frac{1}{4} (\frac{1}{2} ln (2 + 2) - arctan (2 + 1) + \frac{π}{4}) + \frac{1}{4} (\frac{1}{2} ln (2 - 2) + arctan (2 - 1) + \frac{π}{4}))

Simplificar

2 \cdot 2 (- \frac{1}{4} (\frac{1}{2} ln (2 + 2) - arctan (2 + 1) + \frac{π}{4}) + \frac{1}{4} (\frac{1}{2} ln (2 - 2) + arctan (2 - 1) + \frac{π}{4})) : \frac{2 ln ( 2 - 2 ) + 4 arctan ( 1 + 2 ) + 4 arctan ( 2 - 1 ) - 2 ln ( 2 + 2 )}{4 2}

= \frac{2 ln ( 2 - 2 ) + 4 arctan ( 1 + 2 ) + 4 arctan ( 2 - 1 ) - 2 ln ( 2 + 2 )}{4 2}

\int_{0}^{5} \frac{x}{3 x ^{2} + 6} d x

\int_{0}^{\frac{π}{3}} (sin (x)) d x

\int_{0}^{1} sin (y^{2}) d y

\int_{0}^{π} 2 x cos (n x) d x

\int_{0}^{9} 2 x d x