integral from 1 to 4 of x+1

Lösung

\int_{1}^{4} x + 1 d x

\frac{21}{2}

Dezimale

10.5

Schritte zur Lösung

\int_{1}^{4} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x + \int_{1}^{4} 1 d x

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} 1 d x = 3

= \frac{15}{2} + 3

Vereinfache

\frac{15}{2} + 3 : \frac{21}{2}

= \frac{21}{2}

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