integral from 0 to 2 of x^2-4x+4

Lösung

\int_{0}^{2} x^{2} - 4 x + 4 d x

\frac{8}{3}

Dezimale

2.66666 \dots

Schritte zur Lösung

\int_{0}^{2} x^{2} - 4 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 4 x d x + \int_{0}^{2} 4 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} 4 d x = 8

= \frac{8}{3} - 8 + 8

Vereinfache

= \frac{8}{3}

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