integral from 0 to 1 of sqrt(u)

Lösung

\int_{0}^{1} u d u

\frac{2}{3}

Dezimale

0.66666 \dots

Schritte zur Lösung

\int_{0}^{1} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{1}

Berechne die Grenzen:

\frac{2}{3}

= \frac{2}{3}

\int_{1}^{3} (x + \frac{1}{x}) d x

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\int_{0}^{1} x^{\frac{8}{9}} d x